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request.ASP
復制代碼 代碼如下:
dim Https
set Https=server.createobject("MSXML2.XMLHTTP")
'定義一個XMLHTTP對像
Https.open "POST","http://127.0.0.1/testpost/response.ASP",false
Https.send "<?xml version=""1.0""?><misc_command version=""1.6""><command_name>echo</command_name>
<command_data_block><sid>123456</sid><service_id>987654</service_id>
<sp_id>11111</sp_id><sp_password>22222</sp_password></command_data_block>
</misc_command>"
if Https.readystate=4 then
response.write "提交成功"
'readstate讀取狀態為4則成功，繼續后面的，不成功當然就不用繼續處理了
dim objstream
set objstream = Server.CreateObject("adodb.stream")
'定義一個stream，因為讀過來的直接拿出來是亂碼的，所以得處理一下
objstream.Type = 1
objstream.Mode =3
objstream.Open
objstream.Write Https.responseBody
objstream.Position = 0
objstream.Type = 2
objstream.Charset = "GB2312"
html = objstream.ReadText
'轉好碼，就放到html里，好關閉這些對像
objstream.Close
set objstream = nothing
set https=nothing
end if
response.write html
response.ASP
'創建DOMDocument對象
Set xml = Server.CreateObject ("msxml2.DOMDocument")
xml.async = False
'裝載POST數據
xml.Load Request
If xml.parseError.errorCode <> 0 Then
response.write "不能正確接收數據" & "Description: " & xml.parseError.reason & "＜br＞Line: " & xml.parseError.Line
End If
set blogchild=xml.getElementsByTagName("misc_command")
'the_text=blogchild.item(0).childnodes(1).text
'the_text=blogchild.item(0).text
'for i=0 to blogchild.length-1
response.write the_text
利用這種方法，ASP里調用Servlet或Web Service都是很輕松的！
JavaScript技術：利用ASP發送和接收XML數據的處理方法與代碼，轉載需保留來源！
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